Rd Sharma Solutions For Class 8 Chapter 6 Algebraic Expressions And Identities Exercise 6 5 Get Free Pdf
Extended Keyboard Examples Upload Random Compute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, history, geography, engineering, mathematics, linguistics, sports, finance, musicFind the equation of the tangent to the curve y = 2x^2 x 1 at the point where x = 1 To get the required tangent equation we need its gradient and the coordinates of a point it passes through We can then substitute it into the formula y y 1 = m (x x 1 ) 1 Finding the gradient To find the gradient of the tangent, first find the gradient of the curve where x=1 y = 2x 2 x 1 > dy/dx
Y=(x-3)^2+1 graph