[コンプリート！] y=x^3 2x^2-1 263244-Y=(x-3)^2+1 graph

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Extended Keyboard Examples Upload Random Compute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, history, geography, engineering, mathematics, linguistics, sports, finance, musicFind the equation of the tangent to the curve y = 2x^2 x 1 at the point where x = 1 To get the required tangent equation we need its gradient and the coordinates of a point it passes through We can then substitute it into the formula y y 1 = m (x x 1 ) 1 Finding the gradient To find the gradient of the tangent, first find the gradient of the curve where x=1 y = 2x 2 x 1 > dy/dx

Y=(x-3)^2+1 graph

++ 50 ++ y=x^2 2x-8 in factored form 278779-Y=x^2-2x-8 in factored form

Previous Post Previous Answer Which is the completely factored form of 3×2 – 12x – 15?Find the xintercepts/roots and yintercept of a quadratic in factored or standard form without making a table or graphing first a y = (x – 12)(2x 9) b y = 5x 2 9x – 2 What formDivide 22\sqrt {y} by 2 The equation is now solved Swap sides so that all variable terms are on the left hand side Factor x^ {2}2x1 In general, when x^ {2}bxc is a perfect square, it can always be factored as \left (x\frac {b} {2}\right)^ {2}

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Y=x^2-2x-8 in factored form